mysql> select bedrag, jaar, count(*) from subsidies GROUP BY jaar;
+--------+------+----------+
| bedrag | jaar | count(*) |
+--------+------+----------+
|   1239 | 1982 |        1 | 
|   1239 | 1985 |        2 | 
|    620 | 1986 |        2 | 
|   6197 | 1987 |        3 | 
|   1487 | 1988 |        4 | 
|   4958 | 1989 |        3 | 
|   2479 | 1990 |        5 | 
|   5578 | 1991 |        7 | 
|   1735 | 1992 |        4 | 
|   2479 | 1993 |        3 | 
|   2479 | 1994 |        8 | 
|   2355 | 1995 |        5 | 
|   3718 | 1996 |        8 | 
|   3099 | 1997 |       11 | 
|  12890 | 1998 |       11 | 
|   2231 | 1999 |       29 | 
|   3718 | 2000 |      159 | 
| 198315 | 2001 |      151 | 
|  90000 | 2002 |      174 | 
| 180000 | 2003 |      181 | 
| 180000 | 2004 |      207 | 
| 200000 | 2005 |      200 | 
| 600000 | 2006 |      222 | 
| 608751 | 2007 |      221 | 
| 618000 | 2008 |      142 | 
| 618000 | 2009 |       65 | 
+--------+------+----------+
26 rows in set (0.41 sec)